160x-60=35x^2+35x

Solution for 160x-60=35x^2+35x equation:

160x-60=35x^2+35x

We move all terms to the left:

160x-60-(35x^2+35x)=0

We get rid of parentheses

-35x^2+160x-35x-60=0

We add all the numbers together, and all the variables

-35x^2+125x-60=0

a = -35; b = 125; c = -60;
Δ = b2-4ac
Δ = 1252-4·(-35)·(-60)
Δ = 7225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{7225}=85$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(125)-85}{2*-35}=\frac{-210}{-70}
=+3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(125)+85}{2*-35}=\frac{-40}{-70}
=4/7
$